Maximal ideals in integral extensions of local rings
TheoremKernel of reducing polynomial coefficients modulo an ideal#✓fully proved
Let \(A\) be a commutative ring and \(I\) an ideal of \(A\). The kernel of the ring homomorphism \(A[X] \to (A/I)[X]\) that reduces every coefficient modulo \(I\) is the ideal of \(A[X]\) generated by the constant polynomials \(a\) with \(a \in I\).
theorem comap_mapRingHom_bot_eq_map_C_ker (I : Ideal A) :
Ideal.comap (Polynomial.mapRingHom (Ideal.Quotient.mk I)) ⊥ =
Ideal.map Polynomial.C I
TheoremMaximal ideals of a monogenic algebra over a local ring come from residual irreducible factors#✓fully proved
Maximal ideals of a monogenic algebra over a local ring come from residual irreducible factors. Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\), and for \(f \in A[X]\) write \(\bar{f}\) for its image in \((A/\mathfrak{m})[X]\). Let \(g \in A[X]\) and suppose that \(A[X]/(g)\) is integral over \(A\). Then for every maximal ideal \(M\) of \(A[X]/(g)\) there is a polynomial \(q \in A[X]\) such that \(\bar{q}\) is irreducible in \((A/\mathfrak{m})[X]\), \(\bar{q}\) divides \(\bar{g}\), and \(M\) is the ideal of \(A[X]/(g)\) generated by the image of \(\mathfrak{m}\) and the class of \(q\).
theorem exists_irreducible_factor_of_is_maximal (g : A[X])
[Algebra.IsIntegral A (AdjoinRoot g)] (m : Ideal (AdjoinRoot g))
[hm : m.IsMaximal] :
∃ q : A[X],
Irreducible (q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∧
(q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∣
(g.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∧
m = Ideal.map (algebraMap A (AdjoinRoot g))
(IsLocalRing.maximalIdeal A) ⊔
Ideal.span {AdjoinRoot.mk g q}
Uses 1 · Used by 1
TheoremResidual irreducible factors give maximal ideals of a monogenic algebra#✓fully proved
Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\), and for \(f \in A[X]\) write \(\bar{f}\) for its image in \((A/\mathfrak{m})[X]\). Let \(g, q \in A[X]\) be such that \(\bar{q}\) is irreducible in \((A/\mathfrak{m})[X]\) and \(\bar{q}\) divides \(\bar{g}\). Then the ideal of \(A[X]/(g)\) generated by the image of \(\mathfrak{m}\) and the class of \(q\) is maximal.
No integrality assumption on \(A[X]/(g)\) over \(A\) is needed.
theorem is_maximal_of_irreducible_factor (g q : A[X])
(hirr : Irreducible
(q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))))
(hdvd : (q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∣
(g.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A)))) :
(Ideal.map (algebraMap A (AdjoinRoot g)) (IsLocalRing.maximalIdeal A) ⊔
Ideal.span {AdjoinRoot.mk g q}).IsMaximal
TheoremMaximal ideals of a monogenic algebra over a local ring#✓fully proved
Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\), and for \(f \in A[X]\) write \(\bar{f}\) for its image in \((A/\mathfrak{m})[X]\). Let \(g \in A[X]\) and suppose that \(A[X]/(g)\) is integral over \(A\). Then an ideal \(M\) of \(A[X]/(g)\) is maximal if and only if there is a polynomial \(q \in A[X]\) such that \(\bar{q}\) is irreducible in \((A/\mathfrak{m})[X]\), \(\bar{q}\) divides \(\bar{g}\), and \(M\) is the ideal of \(A[X]/(g)\) generated by the image of \(\mathfrak{m}\) and the class of \(q\).
theorem is_maximal_iff_irreducible_factor (g : A[X])
[Algebra.IsIntegral A (AdjoinRoot g)] (m : Ideal (AdjoinRoot g)) :
m.IsMaximal ↔
∃ q : A[X],
Irreducible
(q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∧
(q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∣
(g.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∧
m = Ideal.map (algebraMap A (AdjoinRoot g))
(IsLocalRing.maximalIdeal A) ⊔
Ideal.span {AdjoinRoot.mk g q}
TheoremMaximal ideals of a monogenic algebra over a local ring, monic case#✓fully proved
Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\), and for \(f \in A[X]\) write \(\bar{f}\) for its image in \((A/\mathfrak{m})[X]\). Let \(g \in A[X]\) be monic. Then an ideal \(M\) of \(A[X]/(g)\) is maximal if and only if there is a polynomial \(q \in A[X]\) such that \(\bar{q}\) is irreducible in \((A/\mathfrak{m})[X]\), \(\bar{q}\) divides \(\bar{g}\), and \(M\) is the ideal of \(A[X]/(g)\) generated by the image of \(\mathfrak{m}\) and the class of \(q\).
theorem is_maximal_iff_irreducible_factor_of_monic (g : A[X]) (hg : g.Monic)
(m : Ideal (AdjoinRoot g)) :
m.IsMaximal ↔
∃ q : A[X],
Irreducible
(q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∧
(q.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∣
(g.map (Ideal.Quotient.mk (IsLocalRing.maximalIdeal A))) ∧
m = Ideal.map (algebraMap A (AdjoinRoot g))
(IsLocalRing.maximalIdeal A) ⊔
Ideal.span {AdjoinRoot.mk g q}
Uses 1
TheoremMaximal ideals of an integral algebra over a local ring contain the base maximal ideal#✓fully proved
Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\), and let \(B\) be a commutative \(A\)-algebra that is integral over \(A\). Then every maximal ideal \(M\) of \(B\) contains the ideal of \(B\) generated by the image of \(\mathfrak{m}\).
theorem IsMaximal.map_maximalIdeal_le {A B : Type*} [CommRing A] [IsLocalRing A]
[CommRing B] [Algebra A B] [Algebra.IsIntegral A B]
{m : Ideal B} (hm : m.IsMaximal) :
Ideal.map (algebraMap A B) (IsLocalRing.maximalIdeal A) ≤ m
TheoremMaximal ideals of an integral monogenic algebra over a local ring contain the base maximal ideal#✓fully proved
Maximal ideals of an integral monogenic algebra over a local ring contain the base maximal ideal. Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\), let \(g \in A[X]\), and suppose that \(A[X]/(g)\) is integral over \(A\). Then every maximal ideal \(M\) of \(A[X]/(g)\) contains the ideal of \(A[X]/(g)\) generated by the image of \(\mathfrak{m}\).
theorem isMaximal_map_maximalIdeal_le {A : Type*} [CommRing A] [IsLocalRing A]
{g : Polynomial A} [Algebra.IsIntegral A (AdjoinRoot g)]
{m : Ideal (AdjoinRoot g)} (hm : m.IsMaximal) :
Ideal.map (algebraMap A (AdjoinRoot g)) (IsLocalRing.maximalIdeal A) ≤ m
TheoremMaximal ideals of a monogenic algebra over a local ring contain the base maximal ideal, monic case#✓fully proved
Maximal ideals of a monogenic algebra over a local ring contain the base maximal ideal, monic case. Let \(A\) be a commutative local ring with maximal ideal \(\mathfrak{m}\) and let \(g \in A[X]\) be monic. Then every maximal ideal \(M\) of \(A[X]/(g)\) contains the ideal of \(A[X]/(g)\) generated by the image of \(\mathfrak{m}\).
theorem isMaximal_map_maximalIdeal_le_of_monic {A : Type*} [CommRing A]
[IsLocalRing A] {g : Polynomial A} (hg : g.Monic)
{m : Ideal (AdjoinRoot g)} (hm : m.IsMaximal) :
Ideal.map (algebraMap A (AdjoinRoot g)) (IsLocalRing.maximalIdeal A) ≤ m
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