Cohomology of p-groups and the Frattini subgroup

DefinitionCentre of the Frattini subgroup#✓fully proved

An element \(x\) of a group \(G\) lies in the centre \(Z(\Phi(G))\) of the Frattini subgroup \(\Phi(G)\) when \(x \in \Phi(G)\) and \(xy = yx\) for every \(y \in \Phi(G)\).

def InFrattiniCenter {G : Type*} [Group G] (x : G) : Prop :=
  x ∈ frattini G ∧ ∀ y ∈ frattini G, x * y = y * x
Used by 1

DefinitionVanishing first cohomology of \(G/\Phi(G)\) in \(Z(\Phi(G))\)#✓fully proved

Let \(G\) be a group, let \(\Phi(G)\) be its Frattini subgroup and let \(Z(\Phi(G))\) be the centre of \(\Phi(G)\). The property holds when every map \(\delta \colon G \to Z(\Phi(G))\) with \(\delta(gh) = \delta(g)\, g\, \delta(h)\, g^{-1}\) for all \(g, h \in G\) and \(\delta(g) = 1\) for all \(g \in \Phi(G)\) is a coboundary: there is an \(a \in Z(\Phi(G))\) with \(\delta(g) = g a g^{-1} a^{-1}\) for all \(g \in G\).

Such maps \(\delta\) are exactly the inflations to \(G\) of the 1-cocycles of \(G/\Phi(G)\) with values in \(Z(\Phi(G))\) for the conjugation action, so the property says \(H^1(G/\Phi(G), Z(\Phi(G))) = 0\).

def FrattiniCenterH1Trivial (G : Type*) [Group G] : Prop :=
  ∀ δ : G → G, (∀ g, InFrattiniCenter (δ g)) → (∀ g h, δ (g * h) = δ g * (g * δ h * g⁻¹)) →
    (∀ g ∈ frattini G, δ g = 1) → ∃ a : G, InFrattiniCenter a ∧ ∀ g, δ g = g * a * g⁻¹ * a⁻¹
Uses 1 · Used by 1

DefinitionKourovka Problem 17.2 (a non-abelian \(p\)-group with trivial \(H^1\))#✓fully proved

The statement, a question of P. Schmid recorded by A. Abdollahi, that there exist a prime \(p\) and a finite non-abelian \(p\)-group \(G\) such that, writing \(\Phi(G)\) for the Frattini subgroup of \(G\) and \(Z(\Phi(G))\) for its centre, the first cohomology group \(H^1(G/\Phi(G), Z(\Phi(G)))\) for the conjugation action of \(G/\Phi(G)\) on \(Z(\Phi(G))\) is trivial.

def nonabelianPGroupFrattiniCenterH1Trivial : Prop :=
  ∃ (p : ℕ) (G : Type) (_ : Group G) (_ : Finite G), p.Prime ∧ IsPGroup p G ∧
    (∃ a b : G, a * b ≠ b * a) ∧ FrattiniCenterH1Trivial G
Uses 1 · Used by 1

TheoremA non-abelian \(p\)-group with \(H^1(G/\Phi(G), Z(\Phi(G))) = 0\) (Kourovka 17.2)#●ready to prove

There exist a prime \(p\) and a finite non-abelian \(p\)-group \(G\) such that, writing \(\Phi(G)\) for the Frattini subgroup of \(G\) and \(Z(\Phi(G))\) for its centre, the first cohomology group \(H^1(G/\Phi(G), Z(\Phi(G)))\) for the conjugation action of \(G/\Phi(G)\) on \(Z(\Phi(G))\) is trivial.

This answers Kourovka Problem 17.2 in the affirmative: the Kourovka Archive answers "Yes, it does", citing Abdollahi (2011).

public theorem_wanted nonabelianPGroupFrattiniCenterH1Trivial_holds :
    nonabelianPGroupFrattiniCenterH1Trivial
Sources
  • E. I. Khukhro and V. D. Mazurov (eds.), Unsolved Problems in Group Theory: The Kourovka Notebook, 21st issue, arXiv:1401.0300v49 (2026), Archive of Solved Problems, Problem 17.2 (A. Abdollahi); resolution: A. Abdollahi, J. Algebra 342 (2011), 154-160, Kourovka Archive, Problem 17.2 (Yes, it does).
Uses 1
3 fully proved1 ready to prove

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