Unions of progression-free sets

DefinitionSets with uniformly large 3AP-free subsets#✓fully proved

A set \(A\) of natural numbers has this property if there is a real number \(\varepsilon > 0\) such that every finite subset \(B \subseteq A\) contains a subset \(C \subseteq B\) with \(|C| \ge \varepsilon |B|\) that contains no nontrivial three-term arithmetic progression, that is, no \(a, b, c \in C\) with \(a + c = 2b\) and \(a \ne b\).

def HasFew3APs (A : Set ℕ) := ∃ (ε : ℝ), ε > 0 ∧
  ∀ (B : Set ℕ), B ⊆ A → Finite B →
  ∃ (C : Set ℕ), C ⊆ B ∧ C.ncard ≥ ε * B.ncard ∧ ThreeAPFree C
Used by 1

DefinitionErdős Problem 847#✓fully proved

Call a set of natural numbers 3AP-free if it contains no \(a, b, c\) with \(a + c = 2b\) and \(a \ne b\). The proposition asserts that every infinite set \(A\) of natural numbers such that, for some real number \(\varepsilon > 0\), every finite subset \(B \subseteq A\) has a 3AP-free subset of size at least \(\varepsilon |B|\), is a finite union of 3AP-free sets: there are a natural number \(n\) and 3AP-free sets \(S_0, \dots, S_{n-1}\) of natural numbers with \(A = S_0 \cup \dots \cup S_{n-1}\).

def conjecture : Prop :=
  ∀ (A : Set ℕ), Infinite A → HasFew3APs A →
    ∃ n, ∃ (S : Fin n → Set ℕ), (∀ i, ThreeAPFree (S i)) ∧ A = ⋃ i : Fin n, S i
Uses 1 · Used by 1

TheoremErdős Problem 847 is false#●ready to prove

Call a set of natural numbers 3AP-free if it contains no \(a, b, c\) with \(a + c = 2b\) and \(a \ne b\). There is an infinite set \(A\) of natural numbers such that, for some real number \(\varepsilon > 0\), every finite subset \(B \subseteq A\) has a 3AP-free subset of size at least \(\varepsilon |B|\), but \(A\) is not the union of finitely many 3AP-free sets of natural numbers.

public theorem_wanted conjecture_refuted : ¬ conjecture
Sources
  • Christian Reiher, Vojtěch Rödl, and Marcelo Sales, Colouring versus density in integers and Hales–Jewett cubes, Journal of the London Mathematical Society (2024), e12987, https://doi.org/10.1112/jlms.12987.
Uses 1
Statement usesErdős Problem 847
2 fully proved1 ready to prove

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