Sylvester–Schur theorem
- Sylvester-Schur: binomial and consecutive forms
- Power-of-four bounds for Sylvester-Schur
- Large residual estimates for the Sylvester-Schur theorem
- Prime-counting estimates for Sylvester-Schur
- Binomial factorization bounds for Sylvester-Schur
- Erdős layer products for Sylvester-Schur
- Large-prime criteria for Sylvester-Schur
- Conditional Sylvester-Schur consequences
- Block-level reductions for the Sylvester-Schur theorem
- Finite residual checks for the Sylvester-Schur theorem
LemmaPrime-counting estimate for Sylvester–Schur when \(38 \le n < 945\)#✓fully proved
For all natural numbers \(n\) and \(k\) with \(38 \le n < 945\) and \(k \ge 1291\), we have \(n! \cdot (k + n - 1)^{\pi(n)} < k^n\), where \(\pi(n)\) denotes the number of primes at most \(n\).
The proof checks finitely many explicit numerical certificates.
lemma second_residual_mid_primeCounting_lt_start_pow {n k : ℕ}
(hn38 : 38 ≤ n) (hnlt945 : n < 945) (hk1291 : 1291 ≤ k) :
Nat.factorial n * (k + n - 1) ^ Nat.primeCounting n < k ^ n
Used by 1
LemmaErdős key lemma#✓fully proved
For all natural numbers \(n\) and \(k\) with \(1 \le n < k\), the binomial coefficient \(\binom{k + n - 1}{n}\) has a prime factor \(p > n\).
This is the binomial form of the Sylvester–Schur theorem, as in Erdős's 1934 proof. The case \(n = 1\) is immediate, and the cases \(k = n + 1\) and \(k = n + 2\) follow directly from Bertrand's postulate.
lemma erdos_choose_prime_factor_gt (n : ℕ) (hn : 1 ≤ n) (k : ℕ) (hk : n < k) :
∃ p : ℕ, p.Prime ∧ n < p ∧ p ∣ Nat.choose (k + n - 1) n
Uses 30 · Used by 1
TheoremSylvester–Schur theorem#✓fully proved
Let \(n\) and \(k\) be natural numbers with \(0 < k < n\). Then some prime \(p > k\) divides the product \(n(n+1)\cdots(n+k-1)\) of the \(k\) consecutive integers starting at \(n\).
theorem exists_prime_gt_and_dvd_ascFactorial {n k : ℕ} (hk : 0 < k) (hkn : k < n) :
∃ p : ℕ, p.Prime ∧ k < p ∧ p ∣ n.ascFactorial k
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