Skip to content

Nonattacking bishops and anassas

DefinitionNonattacking placements#✓fully proved

Let \(B\) be a board, that is, a finite set of squares \((i, j) \in \mathbb{Z}^2\), let \(M\) be a list of basic moves \(v \in \mathbb{Z}^2\), and let \(k\) be a natural number. The nonattacking placements of \(k\) pieces with basic moves \(M\) on \(B\) are the \(k\)-element subsets \(S \subseteq B\) such that for all distinct squares \(p, q \in S\) and every move \(v \in M\), the difference \(q - p\) is not parallel to \(v\), that is, \((q_1 - p_1) v_2 \ne (q_2 - p_2) v_1\).

public def nonattackingPlacements (B : Finset (ℤ × ℤ)) (M : List (ℤ × ℤ)) (k : ℕ) :
    Finset (Finset (ℤ × ℤ)) :=
  (B.powersetCard k).filter fun S =>
    ∀ p ∈ S, ∀ q ∈ S, p ≠ q → ∀ v ∈ M, (q.1 - p.1) * v.2 ≠ (q.2 - p.2) * v.1
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 1.
Used by 5

TheoremExactly one nonattacking placement of no pieces#✓fully proved

For every board \(B\), a finite set of squares of \(\mathbb{Z}^2\), and every list \(M\) of basic moves in \(\mathbb{Z}^2\), there is exactly one nonattacking placement of \(0\) pieces with basic moves \(M\) on \(B\).

public theorem card_nonattackingPlacements_zero (B : Finset (ℤ × ℤ)) (M : List (ℤ × ℤ)) :
    (nonattackingPlacements B M 0).card = 1
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 1.
Uses 1

DefinitionThe square board#✓fully proved

For a natural number \(m\), the square board \(S_m\) is the set of squares \((i, j) \in \mathbb{Z}^2\) with \(1 \le i \le m\) and \(1 \le j \le m\).

public def squareBoard (m : ℕ) : Finset (ℤ × ℤ) :=
  Icc (1 : ℤ) m ×ˢ Icc (1 : ℤ) m
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 2.
Used by 4

DefinitionWhite squares of the square board#✓fully proved

For a natural number \(m\), the white squares of the square board \(S_m = [1, m]^2\) are the integer squares \((i, j) \in S_m\) for which \(i + j\) is even.

public def whiteSquares (m : ℕ) : Finset (ℤ × ℤ) :=
  (squareBoard m).filter fun s => Even (s.1 + s.2)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 2, Table 1.
Uses 1 · Used by 1

DefinitionBlack squares of the square board#✓fully proved

For a natural number \(m\), the black squares of the \(m \times m\) board \(S_m = [1, m]^2\) are the squares \((i, j) \in S_m\) with \(i + j\) odd.

public def blackSquares (m : ℕ) : Finset (ℤ × ℤ) :=
  (squareBoard m).filter fun s => Odd (s.1 + s.2)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 2, Table 1.
Uses 1 · Used by 1

DefinitionBasic moves of the bishop#✓fully proved

The basic moves of the bishop are the two vectors \((1, 1)\) and \((-1, 1)\) in \(\mathbb{Z}^2\).

public def bishopMoves : List (ℤ × ℤ) := [(1, 1), (-1, 1)]
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 2.
Used by 3

DefinitionBasic moves of the anassa#✓fully proved

The basic moves of the anassa are the two vectors \((0, 1)\) and \((1, 1)\) in \(\mathbb{Z}^2\).

public def anassaMoves : List (ℤ × ℤ) := [(0, 1), (1, 1)]
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 3.
Used by 1

DefinitionNonattacking bishops on a square board#✓fully proved

For natural numbers \(m\) and \(k\), \(B_S(m, k)\) is the number of ways to place \(k\) nonattacking bishops on the \(m \times m\) board \(S_m = [1, m]^2\), that is, the number of \(k\)-element subsets of \(S_m\) no two of whose squares lie on a common line of slope \(1\) or \(-1\).

public def bishopsSquare (m k : ℕ) : ℕ :=
  (nonattackingPlacements (squareBoard m) bishopMoves k).card
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 2.1.
Uses 3 · Used by 3

DefinitionNonattacking bishops on the white squares#✓fully proved

For natural numbers \(m\) and \(k\), \(R_W(m, k)\) is the number of \(k\)-element sets of white squares of the \(m \times m\) board \(S_m = [1, m]^2\) (the squares \((i, j)\) with \(i + j\) even) no two of which lie on a common line of slope \(1\) or \(-1\), that is, the number of ways to place \(k\) nonattacking bishops on the white squares of \(S_m\).

In the source, \(R_W(m, k)\) counts placements of \(k\) nonattacking rooks on the white board \(W_m\), whose rows and columns are the diagonals of the white squares of \(S_m\).

public def bishopsWhite (m k : ℕ) : ℕ :=
  (nonattackingPlacements (whiteSquares m) bishopMoves k).card
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 2.2.
Uses 3 · Used by 3

DefinitionNonattacking bishops on the black squares#✓fully proved

For natural numbers \(m\) and \(k\), \(R_K(m, k)\) is the number of \(k\)-element sets of black squares of the \(m \times m\) board \(S_m = [1, m]^2\) (the squares \((i, j)\) with \(i + j\) odd) no two of which lie on a common line of slope \(1\) or \(-1\), that is, the number of ways to place \(k\) nonattacking bishops on the black squares of \(S_m\).

In the source, \(R_K(m, k)\) counts placements of \(k\) nonattacking rooks on the black board \(K_m\), whose rows and columns are the diagonals of the black squares of \(S_m\).

public def bishopsBlack (m k : ℕ) : ℕ :=
  (nonattackingPlacements (blackSquares m) bishopMoves k).card
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 2.2.
Uses 3 · Used by 3

DefinitionNonattacking anassas by number below the diagonal#✓fully proved

For natural numbers \(m\), \(k\) and \(p\), \(A_S(m, k, p)\) is the number of nonattacking placements of \(k\) anassas on the square board \(S_m = \{1, \dots, m\}^2\) (that is, of \(k\)-element sets of squares of \(S_m\) no two of which lie on a common line in the direction \((0, 1)\) or \((1, 1)\)) in which exactly \(p\) of the squares \((i, j)\) satisfy \(j < i\), that is, lie strictly below the main diagonal.

public def anassasBelow (m k p : ℕ) : ℕ :=
  ((nonattackingPlacements (squareBoard m) anassaMoves k).filter fun S =>
    (S.filter fun s => s.2 < s.1).card = p).card
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 3.1.
Uses 3 · Used by 4

DefinitionExtended Stirling numbers of the second kind#✓fully proved

Knuth's extended Stirling number of the second kind at integers \(n\) and \(k\) is the natural number equal to the Stirling number of the second kind \(S(n, k)\) if \(n \ge 0\) and \(k \ge 0\), equal to the unsigned Stirling number of the first kind \(c(-k, -n)\) if \(n < 0\) and \(k < 0\), and equal to \(0\) otherwise. Here \(c(j, i)\) is the number of permutations of \(j\) elements with exactly \(i\) cycles.

public def extStirlingSecond (n k : ℤ) : ℕ :=
  if 0 ≤ n ∧ 0 ≤ k then Nat.stirlingSecond n.toNat k.toNat
  else if n < 0 ∧ k < 0 then Nat.stirlingFirst (-k).toNat (-n).toNat
  else 0
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 1 (extended Stirling numbers, with the identity {-j, -k} = [k, j]).
Used by 9

TheoremExtended Stirling numbers at natural arguments#✓fully proved

For all natural numbers \(n\) and \(k\), the extended Stirling number of the second kind at \((n, k)\) equals the Stirling number of the second kind \(S(n, k)\).

public theorem extStirlingSecond_natCast (n k : ℕ) :
    extStirlingSecond n k = Nat.stirlingSecond n k
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Section 1.
Uses 1

TheoremExtended Stirling numbers at negative arguments#✓fully proved

For all positive integers \(a\) and \(b\), the extended Stirling number of the second kind at \((-a, -b)\) equals the unsigned Stirling number of the first kind \(c(b, a)\), the number of permutations of \(b\) elements with exactly \(a\) cycles.

public theorem extStirlingSecond_neg_neg (a b : ℕ) (ha : 0 < a) (hb : 0 < b) :
    extStirlingSecond (-(a : ℤ)) (-(b : ℤ)) = Nat.stirlingFirst b a
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, proof of Theorem 2.2.
Uses 1

DefinitionSantos's coefficients#✓fully proved

For natural numbers \(i\), \(p\), \(q\) and a complex number \(z\), Santos's coefficient \(\beta_i(p, q, z)\) is the complex number

\[ \beta_i(p, q, z) = 2^{-2q} \sum_{b=\max(0, i-p)}^{q} 2^b \binom{2q-b}{q} \sum_{a=0}^{b} \binom{p+b-q-z}{a} \binom{q+z}{b-a} \binom{a-q}{p+b-i}, \]

where \(\binom{w}{n} = w(w-1)\cdots(w-n+1)/n!\) for complex \(w\) and natural \(n\).

public noncomputable def santosBeta (i p q : ℕ) (z : ℂ) : ℂ :=
  1 / 2 ^ (2 * q) *
    ∑ b ∈ Icc (i - p) q, 2 ^ b * ((2 * q - b).choose q : ℂ) *
      ∑ a ∈ range (b + 1),
        Ring.choose ((p : ℂ) + b - q - z) a * Ring.choose ((q : ℂ) + z) (b - a) *
          Ring.choose ((a : ℂ) - q) (p + b - i)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Lemma 2.7, equation (9).
Used by 4

TheoremSantos's coefficient with all indices zero#✓fully proved

For every complex number \(z\), Santos's coefficient satisfies \(\beta_0(0, 0, z) = 1\).

public theorem santosBeta_zero (z : ℂ) : santosBeta 0 0 0 z = 1
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Lemma 2.7.
Uses 1 · Used by 1

DefinitionConstituent coefficients for bishops on one color#✓fully proved

For natural numbers \(k\), \(d\) and a complex number \(z\), the constituent coefficient \(c_{k,d}(z)\) is

\[c_{k,d}(z) = \sum_{i=d}^{2k} \frac{(-1)^{i-d}}{i!} {i \brack d} \sum_{p=\max(0, i-k)}^{k} \sum_{j=p}^{k} S_2(p+j, p) \, \beta_i(p+j, k-j, z),\]

where \({i \brack d}\) is the unsigned Stirling number of the first kind, \(S_2(n, r)\) is the 2-associated Stirling number of the second kind, and \(\beta_i(p, q, z)\) is the coefficient \(\beta\) of Santos's Lemma 2.7.

Taking \(z = -\pi(m)\) and \(z = \pi(m)\), where \(\pi(m) \in \{0, 1\}\) is the parity of \(m\), gives the coefficients of \(m^d\) in the quasi-polynomials (13) and (14) for \(k\) bishops on the white and black squares.

public noncomputable def bishopColorQuasiCoeff (k d : ℕ) (z : ℂ) : ℂ :=
  ∑ i ∈ Icc d (2 * k), (-1) ^ (i - d) / (i.factorial : ℂ) * (Nat.stirlingFirst i d : ℂ) *
    ∑ p ∈ Icc (i - k) k, ∑ j ∈ Icc p k,
      (twoAssocStirlingSecond (p + j) p : ℂ) * santosBeta i (p + j) (k - j) z
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 2.8.
Uses 2 · Used by 4

TheoremConstituent coefficient for no bishops#✓fully proved

For every complex number \(z\), the constituent coefficient \(c_{0,0}(z)\) of the bishop quasi-polynomials (the case \(k = d = 0\)) equals \(1\).

public theorem bishopColorQuasiCoeff_zero_zero (z : ℂ) : bishopColorQuasiCoeff 0 0 z = 1
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 2.8.
Uses 4
18 fully proved15 ready to prove

The bishop

TheoremArshon's formula for nonattacking bishops (Kotěšovec's form)#●ready to prove

For all natural numbers \(m\) and \(k\), the number \(B_S(m, k)\) of placements of \(k\) nonattacking bishops on the \(m \times m\) board satisfies

\[ B_S(m, k) = \sum_{j=0}^{m} \sum_{i=0}^{\lfloor (m+1)/2 \rfloor} \binom{\lfloor (m+1)/2 \rfloor}{i} S\bigl(i + \lfloor m/2 \rfloor, m - j\bigr) \sum_{l=0}^{\lfloor m/2 \rfloor} \binom{\lfloor m/2 \rfloor}{l} S\bigl(l + \lfloor (m+1)/2 \rfloor, m - k + j\bigr), \]

where, for integers \(a \ge 0\) and \(b\), \(S(a, b)\) is the Stirling number of the second kind when \(b \ge 0\) and \(0\) when \(b < 0\) (Knuth's extended Stirling numbers of the second kind).

public theorem_wanted bishopsSquare_eq_arshon (m k : ℕ) :
    bishopsSquare m k =
      ∑ j ∈ range (m + 1), ∑ i ∈ range ((m + 1) / 2 + 1),
        ((m + 1) / 2).choose i * extStirlingSecond (i + m / 2 : ℕ) ((m : ℤ) - j) *
          ∑ l ∈ range (m / 2 + 1),
            (m / 2).choose l * extStirlingSecond (l + (m + 1) / 2 : ℕ) ((m : ℤ) - k + j)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 3 (Arshon, Kotěšovec) (jis-2025-25.8.6-thm-3).
Uses 2

TheoremRecurrence for bishops on white squares#●ready to prove

Write \(R_W(m, k)\) for the number of placements of \(k\) nonattacking bishops on the white squares (those \((i, j)\) with \(i + j\) even) of the \(m \times m\) board \([1, m]^2\), and \(\pi(n) \in \lbrace 0, 1 \rbrace\) for the remainder of \(n\) modulo \(2\). For all natural numbers \(m\) and \(k\),

\[ R_W(m + 1, k + 1) = R_W(m, k + 1) + \bigl(m - k + \pi(m + 1)\bigr) R_W(m, k), \]

\(R_W(m, 0) = 1\) and \(R_W(0, k + 1) = 0\).

public theorem_wanted bishopsWhite_recurrence (m k : ℕ) :
    (bishopsWhite (m + 1) (k + 1) : ℤ) =
        bishopsWhite m (k + 1) + ((m : ℤ) - k + ((m + 1) % 2 : ℕ)) * bishopsWhite m k ∧
      bishopsWhite m 0 = 1 ∧ bishopsWhite 0 (k + 1) = 0
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 4 (jis-2025-25.8.6-thm-4).
Uses 1

TheoremRecurrence for bishops on the black squares#●ready to prove

Let \(R_K(m, k)\) be the number of nonattacking placements of \(k\) bishops on the black squares \((i, j)\), with \(i + j\) odd, of the board \(\{1, \dots, m\}^2\), and let \(\pi(m) \in \{0, 1\}\) be the remainder of \(m\) modulo \(2\). For \(m, k \ge 1\),

\[R_K(m, k) = R_K(m-1, k) + (m - k + 1 - \pi(m)) \, R_K(m-1, k-1)\]

in the integers, and for every natural number \(m\), \(R_K(m, 0) = 1\) and \(R_K(0, k) = 0\) for \(k \ge 1\).

public theorem_wanted bishopsBlack_recurrence (m k : ℕ) :
    (bishopsBlack (m + 1) (k + 1) : ℤ) =
        bishopsBlack m (k + 1) + ((m : ℤ) - k + 1 - ((m + 1) % 2 : ℕ)) * bishopsBlack m k ∧
      bishopsBlack m 0 = 1 ∧ bishopsBlack 0 (k + 1) = 0
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 4 (jis-2025-25.8.6-thm-4).
Uses 1

TheoremExtended Stirling formula for bishops on white squares#●ready to prove

For all natural numbers \(m\) and \(k\), the number \(R_W(m, k)\) of placements of \(k\) nonattacking bishops on the white squares (those \((i, j)\) with \(i + j\) even) of the \(m \times m\) board \([1, m]^2\) satisfies

\[ R_W(m, k) = \sum_{j=0}^{k} \binom{\lceil m/2 \rceil}{j} S(m - j, m - k), \]

where \(S(a, b)\) is Knuth's extended Stirling number of the second kind for integers \(a, b\): the Stirling number of the second kind when \(a, b \ge 0\), the unsigned Stirling number of the first kind with arguments \(-b, -a\) when \(a, b < 0\), and \(0\) otherwise.

public theorem_wanted bishopsWhite_eq_sum (m k : ℕ) :
    bishopsWhite m k =
      ∑ j ∈ range (k + 1), ((m + 1) / 2).choose j * extStirlingSecond ((m : ℤ) - j) ((m : ℤ) - k)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 4 (jis-2025-25.8.6-thm-4).
Uses 2

TheoremSum formula for bishops on the black squares#●ready to prove

Let \(R_K(m, k)\) be the number of nonattacking placements of \(k\) bishops on the black squares \((i, j)\), with \(i + j\) odd, of the board \(\{1, \dots, m\}^2\), and let \({n \brace j}\) be Knuth's extended Stirling numbers of the second kind. For all natural numbers \(m\) and \(k\),

\[R_K(m, k) = \sum_{j=0}^{k} \binom{\lfloor m/2 \rfloor}{j} {m-j \brace m-k}.\]
public theorem_wanted bishopsBlack_eq_sum (m k : ℕ) :
    bishopsBlack m k =
      ∑ j ∈ range (k + 1), (m / 2).choose j * extStirlingSecond ((m : ℤ) - j) ((m : ℤ) - k)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 4 (jis-2025-25.8.6-thm-4).
Uses 2

TheoremExtended Stirling formula for bishops on a square board#●ready to prove

For all natural numbers \(m\) and \(k\), the number \(B_S(m, k)\) of placements of \(k\) nonattacking bishops on the \(m \times m\) board satisfies

\[ B_S(m, k) = \sum_{j=0}^{k} \sum_{i=0}^{j} \binom{\lfloor m/2 \rfloor}{i} S(m - i, m - j) \sum_{l=0}^{k-j} \binom{\lceil m/2 \rceil}{l} S(m - l, m - k + j), \]

where \(S(a, b)\) is Knuth's extended Stirling number of the second kind for integers \(a, b\): the Stirling number of the second kind when \(a, b \ge 0\), the unsigned Stirling number of the first kind with arguments \(-b, -a\) when \(a, b < 0\), and \(0\) otherwise.

public theorem_wanted bishopsSquare_eq_sum (m k : ℕ) :
    bishopsSquare m k =
      ∑ j ∈ range (k + 1), ∑ i ∈ range (j + 1),
        (m / 2).choose i * extStirlingSecond ((m : ℤ) - i) ((m : ℤ) - j) *
          ∑ l ∈ range (k - j + 1),
            ((m + 1) / 2).choose l * extStirlingSecond ((m : ℤ) - l) ((m : ℤ) - k + j)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 6 (jis-2025-25.8.6-thm-6).
Uses 2

TheoremWard's identity for Stirling numbers of the second kind#●ready to prove

For natural numbers \(k \le m\),

\[S(m, m - k) = \sum_{p=0}^{k} S_2(k + p, p) \binom{m}{k + p},\]

where \(S\) denotes the Stirling numbers of the second kind and \(S_2\) the 2-associated Stirling numbers of the second kind.

public theorem_wanted stirlingSecond_sub_eq_sum_associated (m k : ℕ) (hk : k ≤ m) :
    (Nat.stirlingSecond m (m - k) : ℤ) =
      ∑ p ∈ range (k + 1), twoAssocStirlingSecond (k + p) p * m.choose (k + p)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Lemma 8 (jis-2025-25.8.6-lem-8).
Uses 1

TheoremSantos's expansion of a product of binomial coefficients#●ready to prove

For natural numbers \(p\), \(q\) and complex numbers \(x\), \(z\),

\[\binom{2x + z - q}{p} \binom{x}{q} = \sum_{i=0}^{p+q} \beta_i(p, q, z) \binom{2x + z}{i},\]

where \(\beta_i(p, q, z)\) are Santos's coefficients and, for complex \(w\) and natural \(n\), \(\binom{w}{n} = w(w-1)\cdots(w-n+1)/n!\).

public theorem_wanted choose_mul_choose_eq_sum_santosBeta (p q : ℕ) (x z : ℂ) :
    Ring.choose (2 * x + z - q) p * Ring.choose x q =
      ∑ i ∈ range (p + q + 1), santosBeta i p q z * Ring.choose (2 * x + z) i
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Lemma 9 (jis-2025-25.8.6-lem-9).
Uses 1
Statement usesSantos's coefficients

TheoremQuasi-polynomial formula for bishops on white squares#●ready to prove

Write \(R_W(m, k)\) for the number of placements of \(k\) nonattacking bishops on the white squares (those \((i, j)\) with \(i + j\) even) of the \(m \times m\) board \([1, m]^2\), \(\pi(m) \in \lbrace 0, 1 \rbrace\) for the remainder of \(m\) modulo \(2\), and \(c_{k,d}(z) \in \mathbb{C}\) for the constituent coefficient of the bishop colour quasi-polynomials (defined for natural \(k, d\) and complex \(z\)). For all natural numbers \(m\) and \(k\), as complex numbers,

\[ R_W(m, k) = \sum_{d=0}^{2k} c_{k,d}\bigl(-\pi(m)\bigr)\, m^d. \]
public theorem_wanted bishopsWhite_eq_quasi (m k : ℕ) :
    (bishopsWhite m k : ℂ) =
      ∑ d ∈ range (2 * k + 1), bishopColorQuasiCoeff k d (-((m % 2 : ℕ) : ℂ)) * (m : ℂ) ^ d
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 10 (jis-2025-25.8.6-thm-10).
Uses 2

TheoremQuasi-polynomial formula for bishops on the black squares#●ready to prove

Let \(R_K(m, k)\) be the number of nonattacking placements of \(k\) bishops on the black squares \((i, j)\), with \(i + j\) odd, of the board \(\{1, \dots, m\}^2\), and let \(c_{k,d}(z)\) be the constituent coefficients of the bishop quasi-polynomials. For all natural numbers \(m\) and \(k\),

\[R_K(m, k) = \sum_{d=0}^{2k} c_{k,d}(\pi(m)) \, m^d\]

in \(\mathbb{C}\), where \(\pi(m) \in \{0, 1\}\) is the remainder of \(m\) modulo \(2\).

public theorem_wanted bishopsBlack_eq_quasi (m k : ℕ) :
    (bishopsBlack m k : ℂ) =
      ∑ d ∈ range (2 * k + 1), bishopColorQuasiCoeff k d ((m % 2 : ℕ) : ℂ) * (m : ℂ) ^ d
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 10 (jis-2025-25.8.6-thm-10).
Uses 2

TheoremQuasi-polynomial formula for bishops on a square board#●ready to prove

Write \(B_S(m, k)\) for the number of placements of \(k\) nonattacking bishops on the \(m \times m\) board \([1, m]^2\), \(\pi(m) \in \lbrace 0, 1 \rbrace\) for the remainder of \(m\) modulo \(2\), and \(c_{k,d}(z) \in \mathbb{C}\) for the constituent coefficient of the bishop colour quasi-polynomials (defined for natural \(k, d\) and complex \(z\)). For all natural numbers \(m\) and \(k\), as complex numbers,

\[ B_S(m, k) = \sum_{d=0}^{2k} \Biggl( \sum_{j=0}^{k} \sum_{i=0}^{d} c_{j,i}\bigl(-\pi(m)\bigr)\, c_{k-j,\,d-i}\bigl(\pi(m)\bigr) \Biggr) m^d. \]

The factors \(c_{j,i}(-\pi(m))\) and \(c_{k-j,d-i}(\pi(m))\) are the coefficients of the corresponding quasi-polynomial formulas for bishops on the white and on the black squares.

public theorem_wanted bishopsSquare_eq_quasi (m k : ℕ) :
    (bishopsSquare m k : ℂ) =
      ∑ d ∈ range (2 * k + 1),
        (∑ j ∈ range (k + 1), ∑ i ∈ range (d + 1),
          bishopColorQuasiCoeff j i (-((m % 2 : ℕ) : ℂ)) *
            bishopColorQuasiCoeff (k - j) (d - i) ((m % 2 : ℕ) : ℂ)) * (m : ℂ) ^ d
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 10 (jis-2025-25.8.6-thm-10).
Uses 2

The anassa

TheoremRecurrence for anassas below the diagonal#●ready to prove

Let \(A(m, k, p)\) be the number of nonattacking placements of \(k\) anassas on the square board \(\{1, \dots, m\}^2\) with exactly \(p\) of them strictly below the main diagonal, let \({n \brace j}\) be Knuth's extended Stirling numbers of the second kind, and let \(\delta\) be the Kronecker delta. For \(m \ge 1\), \(k \ge 2\) and \(p \ge 1\),

\[A(m, k, p) = A(m-1, k, p) + (m-k+1) A(m-1, k-1, p) + (m-p) A(m-1, k-1, p-1) + (m-p)(m-k+1) A(m-1, k-2, p-1)\]

in the integers. Moreover, for all natural numbers \(m\), \(k\) and \(p\), \(A(0, k, p) = \delta_{k0} \delta_{p0}\), \(A(m, 0, p) = \delta_{p0}\), \(A(m, 1, p) = {m+1 \brace m} \delta_{p0} + {m \brace m-1} \delta_{p1}\) and \(A(m, k, 0) = {m+1 \brace m-k+1}\).

public theorem_wanted anassasBelow_recurrence (m k p : ℕ) :
    ((anassasBelow (m + 1) (k + 2) (p + 1) : ℤ) =
        anassasBelow m (k + 2) (p + 1) + ((m : ℤ) - k) * anassasBelow m (k + 1) (p + 1) +
          ((m : ℤ) - p) * anassasBelow m (k + 1) p +
          ((m : ℤ) - p) * ((m : ℤ) - k) * anassasBelow m k p) ∧
      anassasBelow 0 k p = (if k = 0 ∧ p = 0 then 1 else 0) ∧
      anassasBelow m 0 p = (if p = 0 then 1 else 0) ∧
      anassasBelow m 1 p =
        (if p = 0 then Nat.stirlingSecond (m + 1) m else 0) +
          (if p = 1 then extStirlingSecond m ((m : ℤ) - 1) else 0) ∧
      anassasBelow m k 0 = extStirlingSecond (m + 1 : ℕ) ((m : ℤ) - k + 1)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 11 (jis-2025-25.8.6-thm-11).
Uses 2

TheoremSum formula for anassas below the diagonal#●ready to prove

Let \(A(m, k, p)\) be the number of nonattacking placements of \(k\) anassas on the square board \(\{1, \dots, m\}^2\) with exactly \(p\) of them strictly below the main diagonal, and let \({n \brace j}\) be Knuth's extended Stirling numbers of the second kind. For natural numbers \(m\), \(k\), \(p\) with \(p \le k\),

\[A(m, k, p) = \sum_{j=0}^{p} (m-k+j)_j \binom{k-p-1}{j} \binom{k-j}{k-p} {m+1 \brace m-k+j+1}\]

in the integers, where \((x)_j = x(x-1)\cdots(x-j+1)\) is the falling factorial and \(\binom{k-p-1}{j}\) is the generalized binomial coefficient, so that \(\binom{-1}{j} = (-1)^j\).

public theorem_wanted anassasBelow_eq_sum (m k p : ℕ) (hp : p ≤ k) :
    (anassasBelow m k p : ℤ) =
      ∑ j ∈ range (p + 1),
        (∏ t ∈ range j, ((m : ℤ) - k + j - t)) * Ring.choose ((k : ℤ) - p - 1) j *
          ((k - j).choose (k - p) : ℤ) * extStirlingSecond (m + 1 : ℕ) ((m : ℤ) - k + j + 1)
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 11 (jis-2025-25.8.6-thm-11).
Uses 2

TheoremTotal number of nonattacking anassas on the square board#●ready to prove

For natural numbers \(m\) and \(k\) and each \(p\), let \(A_S(m, k, p)\) be the number of nonattacking placements of \(k\) anassas on the square board \([1, m]^2\) with exactly \(p\) of them strictly below the main diagonal, that is, the number of \(k\)-element sets of squares \((i, j) \in [1, m]^2\) in which no two squares have the same \(i\) or the same \(i - j\) and exactly \(p\) squares satisfy \(j < i\). Then, in \(\mathbb{Q}\),

\[ \sum_{p=0}^{k} A_S(m, k, p) = \sum_{j=0}^{\lceil k/2 \rceil} (m-k+j)_j \left\{ {m \atop m-k+j} \right\} 2^{k-2j} \left( \binom{k-j}{j-1} + \binom{k-j+1}{j} \right), \]

where \((x)_j = x(x-1) \cdots (x-j+1)\) is the falling factorial, \(\binom{k-j}{-1} = 0\), the power \(2^{k-2j}\) has an integer exponent, and \(\left\{ {n \atop i} \right\}\) is Knuth's extension of the Stirling numbers of the second kind to integer arguments; since \(m \ge 0\), here it is the ordinary Stirling number when \(m - k + j \ge 0\) and \(0\) otherwise.

public theorem_wanted sum_anassasBelow_eq (m k : ℕ) :
    (∑ p ∈ range (k + 1), (anassasBelow m k p : ℚ)) =
      ∑ j ∈ range ((k + 1) / 2 + 1),
        (∏ t ∈ range j, ((m : ℚ) - k + j - t)) * extStirlingSecond m ((m : ℤ) - k + j) *
          (2 : ℚ) ^ ((k : ℤ) - 2 * j) *
          ((if j = 0 then 0 else ((k - j).choose (j - 1) : ℚ)) + ((k - j + 1).choose j : ℚ))
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 13 (jis-2025-25.8.6-thm-13).
Uses 2

TheoremPolynomial formula for the number of nonattacking anassas#●ready to prove

For natural numbers \(m\) and \(k\), let \(A_S(m, k, p)\) be the number of nonattacking placements of \(k\) anassas on the square board \([1, m]^2\) with exactly \(p\) of them strictly below the main diagonal, that is, the number of \(k\)-element sets of squares \((i, j) \in [1, m]^2\) in which no two squares have the same \(i\) or the same \(i - j\) and exactly \(p\) squares satisfy \(j < i\). Then, in \(\mathbb{Q}\), \(\sum_{p=0}^{k} A_S(m, k, p) = \sum_{d=0}^{2k} c_d m^d\) with

\[ c_d = \sum_{i=d}^{2k} \frac{(-1)^{i-d}}{i!} \left[ {i \atop d} \right] \sum_{j=0}^{U(i,k)} \alpha(k, j) \sum_{p=L(i,k)}^{k-j} S_2(p+k-j, p) \sum_{b=0}^{j} \binom{p}{b} \binom{k}{j-b} \binom{b}{k+p-i}, \]

where \(\left[ {i \atop d} \right]\) is the unsigned Stirling number of the first kind, \(S_2\) is the 2-associated Stirling number of the second kind, \(\alpha(k, j) = 2^{k-2j} \left( \binom{k-j}{j-1} + \binom{k-j+1}{j} \right) j!\) with \(\binom{k-j}{-1} = 0\) and an integer exponent in \(2^{k-2j}\), \(U(i, k) = \min(\lceil k/2 \rceil, 2k - i)\) and \(L(i, k) = \max(0, i - k)\).

public theorem_wanted sum_anassasBelow_eq_poly (m k : ℕ) :
    (∑ p ∈ range (k + 1), (anassasBelow m k p : ℚ)) =
      ∑ d ∈ range (2 * k + 1),
        (∑ i ∈ Icc d (2 * k), (-1) ^ (i - d) / (i.factorial : ℚ) * (Nat.stirlingFirst i d : ℚ) *
          ∑ j ∈ range (min ((k + 1) / 2) (2 * k - i) + 1),
            (2 : ℚ) ^ ((k : ℤ) - 2 * j) *
              ((if j = 0 then 0 else ((k - j).choose (j - 1) : ℚ)) + ((k - j + 1).choose j : ℚ)) *
              (j.factorial : ℚ) *
              ∑ p ∈ Icc (i - k) (k - j), (twoAssocStirlingSecond (p + k - j) p : ℚ) *
                ∑ b ∈ range (j + 1),
                  (p.choose b : ℚ) * (k.choose (j - b) : ℚ) * (b.choose (k + p - i) : ℚ)) *
          (m : ℚ) ^ d
Sources
  • Eder G. Santos, Counting Nonattacking Chess Piece Placements: Bishops and Anassas, Journal of Integer Sequences 28 (2025), Article 25.8.6, Theorem 16 (jis-2025-25.8.6-thm-16).
Uses 2

The dependency explorer needs JavaScript and its graph data.

Download the complete graph data.