Monochromatic sums equal to perfect powers
DefinitionErdős Problem 439 for squares#✓fully proved
The statement that for every colouring of the positive integers with finitely many colours there are distinct positive integers \(x\) and \(y\) of the same colour such that \(x + y\) is a perfect square.
def monochromaticSquareSum : Prop :=
∀ r : ℕ, ∀ c : ℕ → Fin r, ∃ x y : ℕ, 0 < x ∧ 0 < y ∧ x ≠ y ∧ c x = c y ∧ IsSquare (x + y)
Used by 1
DefinitionErdős Problem 439 for \(k\)-th powers#✓fully proved
The statement that for every integer \(k \ge 2\) and every colouring of the positive integers with finitely many colours there are distinct positive integers \(x\) and \(y\) of the same colour such that \(x + y = z^k\) for some natural number \(z\).
def monochromaticPowerSum : Prop :=
∀ k : ℕ, 2 ≤ k → ∀ r : ℕ, ∀ c : ℕ → Fin r,
∃ x y : ℕ, 0 < x ∧ 0 < y ∧ x ≠ y ∧ c x = c y ∧ ∃ z : ℕ, x + y = z ^ k
Used by 1
TheoremErdős Problem 439 for squares is true#●ready to prove
For every colouring of the positive integers with finitely many colours there are distinct positive integers \(x\) and \(y\) of the same colour such that \(x + y\) is a perfect square.
This is the case \(f(z) = z^2\) of a theorem of Khalfalah and Szemerédi on monochromatic solutions of \(x + y = f(z)\); Erdős, Sárközy and Sós had proved the cases of \(2\) and \(3\) colours.
public theorem_wanted monochromaticSquareSum_holds : monochromaticSquareSum
def monochromaticSquareSum : Prop :=
∀ r : ℕ, ∀ c : ℕ → Fin r, ∃ x y : ℕ, 0 < x ∧ 0 < y ∧ x ≠ y ∧ c x = c y ∧ IsSquare (x + y)
WantedExt/Combinatorics/MonochromaticSquareSumErdosProblem439Wanted.lean:38
Sources
- T. F. Bloom, Erdős Problems, Problem #439, https://www.erdosproblems.com/439 (status PROVED); resolution: A. Khalfalah and E. Szemerédi, On the number of monochromatic solutions of x + y = z², Combin. Probab. Comput. (2006), 213-227, main theorem (a conjecture of Erdős, Roth, Sárközy and Sós): for every nonconstant f ∈ ℤ[z] with 2 ∣ f(z) for some z ∈ ℤ, every finite colouring of the integers has x ≠ y of the same colour with x + y = f(z) (abstract; erdosproblems.com/439), https://doi.org/10.1017/S0963548305007169.
Uses 1
TheoremErdős Problem 439 for \(k\)-th powers is true#●ready to prove
For every integer \(k \ge 2\) and every colouring of the positive integers with finitely many colours there are distinct positive integers \(x\) and \(y\) of the same colour such that \(x + y = z^k\) for some natural number \(z\).
Khalfalah and Szemerédi proved the corresponding statement for \(x + y = f(z)\) for every nonconstant polynomial \(f\) with integer coefficients such that \(f(z)\) is even for some integer \(z\); the polynomial \(f(z) = z^k\) qualifies, since \(f(2) = 2^k\).
public theorem_wanted monochromaticPowerSum_holds : monochromaticPowerSum
def monochromaticPowerSum : Prop :=
∀ k : ℕ, 2 ≤ k → ∀ r : ℕ, ∀ c : ℕ → Fin r,
∃ x y : ℕ, 0 < x ∧ 0 < y ∧ x ≠ y ∧ c x = c y ∧ ∃ z : ℕ, x + y = z ^ k
WantedExt/Combinatorics/MonochromaticSquareSumErdosProblem439Wanted.lean:44
Sources
- T. F. Bloom, Erdős Problems, Problem #439, https://www.erdosproblems.com/439 (status PROVED); resolution: A. Khalfalah and E. Szemerédi, On the number of monochromatic solutions of x + y = z², Combin. Probab. Comput. (2006), 213-227, main theorem (a conjecture of Erdős, Roth, Sárközy and Sós): for every nonconstant f ∈ ℤ[z] with 2 ∣ f(z) for some z ∈ ℤ, every finite colouring of the integers has x ≠ y of the same colour with x + y = f(z) (abstract; erdosproblems.com/439), https://doi.org/10.1017/S0963548305007169.
Uses 1
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