Symmetric peaks and valleys in compositions

DefinitionNumber of symmetric peaks#✓fully proved

For a finite word \(w = w_1 w_2 \cdots w_m\) of natural numbers, a symmetric peak is a factor \(w_i w_{i+1} w_{i+2}\) of three consecutive letters with \(w_i = w_{i+2} < w_{i+1}\). The number of symmetric peaks of \(w\) is the number of indices \(i\) with \(1 \le i \le m - 2\) at which \(w\) has a symmetric peak (overlapping peaks all count); it is \(0\) when \(m < 3\).

def symmetricPeakCount : List ℕ → ℕ
  | a :: b :: c :: t => (if a = c ∧ a < b then 1 else 0) + symmetricPeakCount (b :: c :: t)
  | _ => 0
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Section 1 (symmetric peaks).
Used by 6

DefinitionSum of the heights of symmetric peaks#✓fully proved

For a finite word \(w = w_1 w_2 \cdots w_m\) of natural numbers, a symmetric peak is a factor \(w_i w_{i+1} w_{i+2}\) of three consecutive letters with \(w_i = w_{i+2} < w_{i+1}\), and its height is \(w_{i+1} - w_i\). The symmetric peak height sum of \(w\) is the sum of the heights of the symmetric peaks of \(w\) over all indices \(i\) with \(1 \le i \le m - 2\) at which one occurs; it is \(0\) when \(m < 3\).

def symmetricPeakHeightSum : List ℕ → ℕ
  | a :: b :: c :: t =>
      (if a = c ∧ a < b then b - a else 0) + symmetricPeakHeightSum (b :: c :: t)
  | _ => 0
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Section 1 (heights of symmetric peaks).
Used by 7

DefinitionNumber of symmetric valleys of a word#✓fully proved

For a word \(w = w_1 w_2 \cdots w_\ell\) of natural numbers, a symmetric valley is a position \(i\) with \(1 < i < \ell\) such that \(w_{i-1} = w_{i+1}\) and \(w_i < w_{i-1}\), that is, a factor \(a\,b\,a\) with \(b < a\). The symmetric valley count of \(w\) is the number of such positions; in particular it is \(0\) when \(\ell < 3\).

def symmetricValleyCount : List ℕ → ℕ
  | a :: b :: c :: t => (if a = c ∧ b < a then 1 else 0) + symmetricValleyCount (b :: c :: t)
  | _ => 0
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Section 1 (symmetric valleys).
Used by 3

DefinitionTotal depth of the symmetric valleys of a word#✓fully proved

For a word \(w = w_1 w_2 \cdots w_\ell\) of natural numbers, a symmetric valley is a position \(i\) with \(1 < i < \ell\) such that \(w_{i-1} = w_{i+1}\) and \(w_i < w_{i-1}\); its depth is \(w_{i-1} - w_i\). The symmetric valley depth sum of \(w\) is the sum of the depths of all its symmetric valleys; in particular it is \(0\) when \(\ell < 3\).

def symmetricValleyDepthSum : List ℕ → ℕ
  | a :: b :: c :: t =>
      (if a = c ∧ b < a then a - b else 0) + symmetricValleyDepthSum (b :: c :: t)
  | _ => 0
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Section 1 (depths of symmetric valleys).
Used by 7

TheoremSymmetric peak examples among the compositions of 5#✓fully proved

The symmetric peak height sums of the words \(1\,3\,1\), \(1\,2\,1\,1\), \(1\,1\,2\,1\) and \(1\,1\,1\,1\,1\) are \(2\), \(1\), \(1\) and \(0\) respectively, and the word \(1\,3\,1\) has exactly one symmetric peak.

theorem symmetricPeakHeightSum_examples :
    symmetricPeakHeightSum [1, 3, 1] = 2 ∧ symmetricPeakHeightSum [1, 2, 1, 1] = 1 ∧
      symmetricPeakHeightSum [1, 1, 2, 1] = 1 ∧ symmetricPeakHeightSum [1, 1, 1, 1, 1] = 0 ∧
      symmetricPeakCount [1, 3, 1] = 1
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, example after Corollary 1.
Uses 2

TheoremSymmetric valleys in three compositions of eight#✓fully proved

The word \(2\,1\,2\,1\,2\) has two symmetric valleys and total symmetric valley depth \(2\), the word \(3\,1\,3\,1\) has total symmetric valley depth \(2\), and the word \(3\,2\,3\) has total symmetric valley depth \(1\).

theorem symmetricValleyDepthSum_examples :
    symmetricValleyDepthSum [2, 1, 2, 1, 2] = 2 ∧ symmetricValleyCount [2, 1, 2, 1, 2] = 2 ∧
      symmetricValleyDepthSum [3, 1, 3, 1] = 2 ∧ symmetricValleyDepthSum [3, 2, 3] = 1
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, example after Corollary 2.
Uses 2

TheoremGenerating function of the total symmetric peak height over compositions#●ready to prove

For \(n \ge 0\) let \(\mathrm{hsp}(n)\) be the sum, over all compositions \(c\) of \(n\), of the symmetric peak height sum of the sequence of parts of \(c\). Then in \(\mathbb{Z}[[x]]\)

\[ \left(\sum_{n \ge 0} \mathrm{hsp}(n)\, x^n\right)(1 - 2x)^2 (1 - x^3) = x^4, \]

that is, \(\sum_{n \ge 0} \mathrm{hsp}(n)\, x^n = x^4 / ((1 - 2x)^2 (1 - x^3))\).

public theorem_wanted symmetricPeakHeightSum_compositions_genFun :
    PowerSeries.mk (fun n => ((∑ c : Composition n, symmetricPeakHeightSum c.blocks : ℕ) : ℤ)) *
        ((1 - 2 * X) ^ 2 * (1 - X ^ 3)) = X ^ 4
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Lemma 1, (5).
Uses 1

TheoremBivariate generating function of the total symmetric peak height over compositions#●ready to prove

For \(n, k \ge 0\) let \(\mathrm{hsp}(n, k)\) be the sum, over all compositions \(c\) of \(n\) with exactly \(k\) parts, of the symmetric peak height sum of the sequence of parts of \(c\). Then in the ring \(\mathbb{Z}[y][[x]]\) of formal power series in \(x\) over \(\mathbb{Z}[y]\),

\[ \left(\sum_{n \ge 0} \sum_{k \ge 0} \mathrm{hsp}(n, k)\, y^k x^n\right) (1 - x^3)(1 - x - yx)^2 = y^3 x^4, \]

that is, \(\sum_{n, k \ge 0} \mathrm{hsp}(n, k)\, x^n y^k = y^3 x^4 / ((1 - x^3)(1 - x - yx)^2)\).

public theorem_wanted symmetricPeakHeightSum_compositions_bivariate_genFun :
    PowerSeries.mk (fun n => ∑ c : Composition n,
        Polynomial.C ((symmetricPeakHeightSum c.blocks : ℕ) : ℤ) * Polynomial.X ^ c.length) *
        ((1 - X ^ 3) * (1 - X - PowerSeries.C (Polynomial.X : Polynomial ℤ) * X) ^ 2) =
      PowerSeries.C (Polynomial.X ^ 3 : Polynomial ℤ) * X ^ 4
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Lemma 1.
Uses 1

TheoremGenerating function for the total depth of symmetric valleys over compositions#●ready to prove

For \(n \ge 0\), let \(\operatorname{dsv}(n)\) be the sum, over all compositions \(c\) of \(n\), of the total depth of the symmetric valleys of the sequence of parts of \(c\). Then in the ring \(\mathbb{Z}[[x]]\) of formal power series,

\[\Big(\sum_{n \ge 0} \operatorname{dsv}(n)\, x^n\Big)(1-2x)^2(1-x^3)(1-x^2)^2 = x^5 - 2x^6 + x^7,\]

that is, \(\sum_{n \ge 0} \operatorname{dsv}(n)\, x^n\) equals \((x^5 - 2x^6 + x^7)/((1-2x)^2(1-x^3)(1-x^2)^2)\).

public theorem_wanted symmetricValleyDepthSum_compositions_genFun :
    PowerSeries.mk (fun n => ((∑ c : Composition n, symmetricValleyDepthSum c.blocks : ℕ) : ℤ)) *
        ((1 - 2 * X) ^ 2 * (1 - X ^ 3) * (1 - X ^ 2) ^ 2) = X ^ 5 - 2 * X ^ 6 + X ^ 7
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Lemma 2, (11).
Uses 1

TheoremClosed form for the total symmetric peak height over compositions#●ready to prove

For \(n \ge 0\) let \(\mathrm{hsp}(n)\) be the sum, over all compositions \(c\) of \(n\), of the symmetric peak height sum of the sequence of parts of \(c\), and let \(\omega_\pm = 1 \pm i\sqrt{3}\). Then for every \(n \ge 0\), as complex numbers,

\[ \mathrm{hsp}(n) = \frac{2^n}{2} \cdot \frac{7n - 24}{49} + \frac{(-33 - 15 i \sqrt{3})(-2)^n}{441\, \omega_+^{n+1}} + \frac{(-33 + 15 i \sqrt{3})(-2)^n}{441\, \omega_-^{n+1}} + \frac{1}{3}. \]
public theorem_wanted symmetricPeakHeightSum_compositions_closed_form (n : ℕ) :
    ((∑ c : Composition n, symmetricPeakHeightSum c.blocks : ℕ) : ℂ) =
      (2 : ℂ) ^ n / 2 * (7 * n - 24) / 49 +
        (-33 - 15 * Complex.I * (Real.sqrt 3 : ℂ)) * (-2) ^ n /
          (441 * (1 + Complex.I * (Real.sqrt 3 : ℂ)) ^ (n + 1)) +
        (-33 + 15 * Complex.I * (Real.sqrt 3 : ℂ)) * (-2) ^ n /
          (441 * (1 - Complex.I * (Real.sqrt 3 : ℂ)) ^ (n + 1)) + 1 / 3
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Corollary 1, (6).
Uses 1

TheoremClosed form for the total depth of symmetric valleys over compositions#●ready to prove

For \(n \ge 0\), let \(\operatorname{dsv}(n)\) be the sum, over all compositions \(c\) of \(n\), of the total depth of the symmetric valleys of the sequence of parts of \(c\), and write \(\omega_\pm = 1 \pm i\sqrt{3}\). Then, as complex numbers,

\[\operatorname{dsv}(n) = \frac{(-6n+7)(-1)^n}{108} + \frac{2^n(21n-79)}{1323} + \frac{(-33-15\sqrt{3}\,i)(-2)^n}{441\,\omega_+^{n+1}} + \frac{(-33+15\sqrt{3}\,i)(-2)^n}{441\,\omega_-^{n+1}} + \frac{1}{12}.\]
public theorem_wanted symmetricValleyDepthSum_compositions_closed_form (n : ℕ) :
    ((∑ c : Composition n, symmetricValleyDepthSum c.blocks : ℕ) : ℂ) =
      (-6 * n + 7) / 108 * (-1) ^ n + (2 : ℂ) ^ n * (21 * n - 79) / 1323 +
        (-33 - 15 * (Real.sqrt 3 : ℂ) * Complex.I) * (-2) ^ n /
          (441 * (1 + Complex.I * (Real.sqrt 3 : ℂ)) ^ (n + 1)) +
        (-33 + 15 * (Real.sqrt 3 : ℂ) * Complex.I) * (-2) ^ n /
          (441 * (1 - Complex.I * (Real.sqrt 3 : ℂ)) ^ (n + 1)) + 1 / 12
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Corollary 2, (12).
Uses 1

TheoremTotal symmetric peak height over compositions with a fixed number of parts#●ready to prove

For \(n, k \ge 0\) let \(\mathrm{hsp}(n, k)\) be the sum, over all compositions \(c\) of \(n\) with exactly \(k\) parts, of the symmetric peak height sum of the sequence of parts of \(c\). If \(k > 3\), then for every \(n \ge 0\)

\[ \mathrm{hsp}(n, k) = (k - 2) \sum_{m=2}^{n-k+1} \sum_{b=1}^{\min(m-1,\, t_m)} \binom{n - 2b - m - 1}{k - 4} (m - b), \qquad t_m = \left\lfloor \frac{n - m - k + 3}{2} \right\rfloor, \]

where an empty sum is \(0\).

public theorem_wanted symmetricPeakHeightSum_compositions_length (n k : ℕ) (hk : 3 < k) :
    ∑ c ∈ Finset.univ.filter (fun c : Composition n => c.length = k),
        symmetricPeakHeightSum c.blocks =
      (k - 2) * ∑ m ∈ Finset.Icc 2 (n - k + 1),
        ∑ b ∈ Finset.Icc 1 (min (m - 1) ((n - m - k + 3) / 2)),
          (n - 2 * b - m - 1).choose (k - 4) * (m - b)
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Theorem 2(a).
Uses 1

TheoremTotal depth of symmetric valleys over compositions with \(k > 3\) parts#●ready to prove

For natural numbers \(n\) and \(k\) with \(k > 3\), the sum, over all compositions \(c\) of \(n\) with exactly \(k\) parts, of the total depth of the symmetric valleys of the sequence of parts of \(c\) equals

\[(k-2) \sum_{m=1}^{\lfloor (n-k+1)/3 \rfloor} \sum_{b=m+1}^{\lfloor (n-m-(k-3))/2 \rfloor} \binom{n-2b-m-1}{k-4}(b-m),\]

where a difference of natural numbers that would be negative is read as \(0\).

public theorem_wanted symmetricValleyDepthSum_compositions_length (n k : ℕ) (hk : 3 < k) :
    ∑ c ∈ Finset.univ.filter (fun c : Composition n => c.length = k),
        symmetricValleyDepthSum c.blocks =
      (k - 2) * ∑ m ∈ Finset.Icc 1 ((n - k + 1) / 3),
        ∑ b ∈ Finset.Icc (m + 1) ((n - m - (k - 3)) / 2),
          (n - 2 * b - m - 1).choose (k - 4) * (b - m)
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Theorem 4(a).
Uses 1

TheoremTotal depth of symmetric valleys over compositions with three parts#●ready to prove

For every natural number \(n\), the sum, over all compositions \(c\) of \(n\) with exactly three parts, of the total depth of the symmetric valleys of the sequence of parts of \(c\) equals \(\sum_{m=1}^{\lfloor (n-2)/3 \rfloor} d_m\), where \(d_m = (n-3m)/2\) if \(n - m\) is even and \(d_m = 0\) otherwise.

public theorem_wanted symmetricValleyDepthSum_compositions_length_three (n : ℕ) :
    ∑ c ∈ Finset.univ.filter (fun c : Composition n => c.length = 3),
        symmetricValleyDepthSum c.blocks =
      ∑ m ∈ Finset.Icc 1 ((n - 2) / 3), if Even (n - m) then (n - 3 * m) / 2 else 0
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Theorem 4(b).
Uses 1

TheoremExpected symmetric peaks and valleys in geometric words#●ready to prove

Let \(n \ge 2\), let \(0 < p < 1\) and \(q = 1 - p\), and let \(X_1, \dots, X_n\) be independent random variables, each geometric on \(\{0, 1, 2, \dots\}\) with \(\Pr(X_i = k) = q^k p\), and consider the word \(X_1 X_2 \cdots X_n\). The expected number of its symmetric peaks is \(p^2 q (n - 2)/(1 - q^3)\), the expected number of its symmetric valleys is \(p^2 \left(\frac{1}{1 - q^2} - \frac{1}{1 - q^3}\right)(n - 2)\), the expected sum of the heights of its symmetric peaks is \(p q (n - 2)/(1 - q^3)\), and the expected sum of the depths of its symmetric valleys is \(q \left(\frac{p}{1 - q^3} - \frac{1}{(1 + q)^2}\right)(n - 2)\).

public theorem_wanted integral_symmetricPeakValley_geometric (n : ℕ) (hn : 2 ≤ n)
    (p : unitInterval) (hp0 : p ≠ 0) (hp1 : p ≠ 1) :
    let q : ℝ := 1 - p
    let μ := Measure.pi fun _ : Fin n => geometricMeasure p
    ∫ x, (symmetricPeakCount (List.ofFn x) : ℝ) ∂μ = p ^ 2 * q / (1 - q ^ 3) * (n - 2) ∧
      ∫ x, (symmetricValleyCount (List.ofFn x) : ℝ) ∂μ =
        p ^ 2 * (1 / (1 - q ^ 2) - 1 / (1 - q ^ 3)) * (n - 2) ∧
      ∫ x, (symmetricPeakHeightSum (List.ofFn x) : ℝ) ∂μ = p * q / (1 - q ^ 3) * (n - 2) ∧
      ∫ x, (symmetricValleyDepthSum (List.ofFn x) : ℝ) ∂μ =
        q * (p / (1 - q ^ 3) - 1 / (1 + q) ^ 2) * (n - 2)
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Theorem 5.
Uses 4

TheoremTrivariate generating function for symmetric peaks in compositions#●ready to prove

For a composition \(c\) write \(\ell(c)\) for its number of parts, \(\mathrm{sp}(c)\) for the number of symmetric peaks and \(\mathrm{hsp}(c)\) for the symmetric peak height sum of its sequence of parts. In the ring \(\mathbb{Z}[y, q, h][[x]]\) of formal power series in \(x\) whose coefficients are polynomials in \(y, q, h\) with integer coefficients,

\[ \sum_{n \ge 0} \sum_{c \models n} x^n y^{\ell(c)} q^{\mathrm{sp}(c)} h^{\mathrm{hsp}(c)} = \frac{1}{1 - \sum_{a \ge 1} \frac{x^a y}{1 - y^2 x^{2a+1} \left(\frac{qh}{1 - hx} - \frac{1}{1 - x}\right)}}, \]

where \(c \models n\) ranges over the compositions of \(n\) and \(\frac{qh}{1 - hx} - \frac{1}{1 - x}\) stands for the series \(\sum_{j \ge 0} (q h^{j+1} - 1) x^j\). Precisely: for every \(n \ge 0\) the coefficients of \(x^n\) on the two sides agree when the sum over \(a\) is restricted to \(1 \le a \le n\) (the terms with \(a > n\) do not contribute to them).

public theorem_wanted symmetricPeak_compositions_trivariate_genFun (n : ℕ) :
    PowerSeries.coeff n (PowerSeries.mk fun m => ∑ c : Composition m,
        MvPolynomial.X (0 : Fin 3) ^ c.length * MvPolynomial.X 1 ^ symmetricPeakCount c.blocks *
          MvPolynomial.X 2 ^ symmetricPeakHeightSum c.blocks : PowerSeries (MvPolynomial (Fin 3) ℤ)) =
      PowerSeries.coeff n (PowerSeries.invOfUnit (1 - ∑ a ∈ Finset.Icc 1 n,
        X ^ a * PowerSeries.C (MvPolynomial.X 0) *
          PowerSeries.invOfUnit (1 - PowerSeries.C (MvPolynomial.X 0 ^ 2) * X ^ (2 * a + 1) *
            PowerSeries.mk fun j =>
              MvPolynomial.X 1 * MvPolynomial.X 2 ^ (j + 1) - 1) 1) 1)
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Theorem 1.
Uses 2

TheoremTrivariate generating function for symmetric valleys in compositions#●ready to prove

For a composition \(c\) write \(\ell(c)\) for its number of parts, \(\mathrm{sv}(c)\) for the number of symmetric valleys and \(\mathrm{dsv}(c)\) for the symmetric valley depth sum of its sequence of parts. In the ring \(\mathbb{Z}[y, p, d][[x]]\) of formal power series in \(x\) whose coefficients are polynomials in \(y, p, d\) with integer coefficients,

\[ \sum_{n \ge 0} \sum_{c \models n} x^n y^{\ell(c)} p^{\mathrm{sv}(c)} d^{\mathrm{dsv}(c)} = \frac{1}{1 - \sum_{a \ge 1} \frac{x^a y}{1 - y^2 x^{a+1} \sum_{b=1}^{a-1} (p d^{a-b} - 1) x^{b-1}}}, \]

where \(c \models n\) ranges over the compositions of \(n\). Precisely: for every \(n \ge 0\) the coefficients of \(x^n\) on the two sides agree when the sum over \(a\) is restricted to \(1 \le a \le n\) (the terms with \(a > n\) do not contribute to them). The inner sum equals \(p(x^{a-1} - d^{a-1})/(x/d - 1) - (x^{a-1} - 1)/(x - 1)\).

Corrected reading: the paper prints \((p x^{a-1} - d^{a-1})/(x/d - 1)\), with \(p\) on the first term only; that is false (at \(n = 3\) it gives the composition \(111\) a symmetric valley of depth \(0\)). The corrected term \(p(x^{a-1} - d^{a-1})/(x/d - 1)\) is the penultimate line of the paper's proof, \(x^a y^2 p d^a ((x/d)^a - x/d)/(x/d - 1)\), and agrees with the paper's specialization \(d = 1\), \((x^{a-1} - 1)(p - 1)/(x - 1)\).

public theorem_wanted symmetricValley_compositions_trivariate_genFun (n : ℕ) :
    PowerSeries.coeff n (PowerSeries.mk fun m => ∑ c : Composition m,
        MvPolynomial.X (0 : Fin 3) ^ c.length * MvPolynomial.X 1 ^ symmetricValleyCount c.blocks *
          MvPolynomial.X 2 ^ symmetricValleyDepthSum c.blocks :
        PowerSeries (MvPolynomial (Fin 3) ℤ)) =
      PowerSeries.coeff n (PowerSeries.invOfUnit (1 - ∑ a ∈ Finset.Icc 1 n,
        X ^ a * PowerSeries.C (MvPolynomial.X 0) *
          PowerSeries.invOfUnit (1 - PowerSeries.C (MvPolynomial.X 0 ^ 2) * X ^ (a + 1) *
            ∑ b ∈ Finset.Ico 1 a,
              PowerSeries.C (MvPolynomial.X 1 * MvPolynomial.X 2 ^ (a - b) - 1) * X ^ (b - 1)) 1) 1)
Sources
  • Walaa Asakly and Noor Kezil, The Heights of Symmetric Peaks and the Depths of Symmetric Valleys over Compositions of an Integer, INTEGERS 26 (2026), Article A65, Theorem 3.
Uses 2
6 fully proved11 ready to prove

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